Solve for x
x=\frac{z}{2}-\frac{4y}{3}+12
Solve for y
y=\frac{3\left(24+z-2x\right)}{8}
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6x-3z=72-8y
Subtract 8y from both sides.
6x=72-8y+3z
Add 3z to both sides.
6x=72+3z-8y
The equation is in standard form.
\frac{6x}{6}=\frac{72+3z-8y}{6}
Divide both sides by 6.
x=\frac{72+3z-8y}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{z}{2}-\frac{4y}{3}+12
Divide 72-8y+3z by 6.
8y-3z=72-6x
Subtract 6x from both sides.
8y=72-6x+3z
Add 3z to both sides.
8y=72+3z-6x
The equation is in standard form.
\frac{8y}{8}=\frac{72+3z-6x}{8}
Divide both sides by 8.
y=\frac{72+3z-6x}{8}
Dividing by 8 undoes the multiplication by 8.
y=\frac{3z}{8}-\frac{3x}{4}+9
Divide 72-6x+3z by 8.
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