Solve for x
x=-\frac{y}{2}+\frac{4}{3}
Solve for y
y=\frac{8}{3}-2x
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6x=8-3y
Subtract 3y from both sides.
\frac{6x}{6}=\frac{8-3y}{6}
Divide both sides by 6.
x=\frac{8-3y}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{y}{2}+\frac{4}{3}
Divide 8-3y by 6.
3y=8-6x
Subtract 6x from both sides.
\frac{3y}{3}=\frac{8-6x}{3}
Divide both sides by 3.
y=\frac{8-6x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{8}{3}-2x
Divide 8-6x by 3.
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