Solve 68x-112+32x-112+68+3.2

$$68 x - 112 + 32 x - 112 + 68 + 3.2$$

Evaluate

$$100x-152.8$$

Solution Steps

Combine 68x and 32x to get 100x.

$$100x-112-112+68+3.2$$

Subtract 112 from -112 to get -224.

$$100x-224+68+3.2$$

Add -224 and 68 to get -156.

$$100x-156+3.2$$

Add -156 and 3.2 to get -152.8.

$$100x-152.8$$

Differentiate w.r.t. x

$$100$$

Steps Using Derivative Rule for Sum

Combine 68x and 32x to get 100x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(100x-112-112+68+3.2)$$

Subtract 112 from -112 to get -224.

$$\frac{\mathrm{d}}{\mathrm{d}x}(100x-224+68+3.2)$$

Add -224 and 68 to get -156.

$$\frac{\mathrm{d}}{\mathrm{d}x}(100x-156+3.2)$$

Add -156 and 3.2 to get -152.8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(100x-152.8)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$100x^{1-1}$$

Subtract 1 from 1.

$$100x^{0}$$

For any term t except 0, t^{0}=1.

$$100\times 1$$

For any term t, t\times 1=t and 1t=t.

$$100$$