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\frac{68}{2\sqrt{7}}
Factor 28=2^{2}\times 7. Rewrite the square root of the product \sqrt{2^{2}\times 7} as the product of square roots \sqrt{2^{2}}\sqrt{7}. Take the square root of 2^{2}.
\frac{68\sqrt{7}}{2\left(\sqrt{7}\right)^{2}}
Rationalize the denominator of \frac{68}{2\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
\frac{68\sqrt{7}}{2\times 7}
The square of \sqrt{7} is 7.
\frac{34\sqrt{7}}{7}
Cancel out 2 in both numerator and denominator.