Solve 6400*(1+75/1000)^3

$$6400 \times ( 1 + \frac { 75 } { 1000 } ) ^ { 3 }$$

Evaluate

$$\frac{79507}{10}=7950.7$$

Solution Steps

Reduce the fraction \frac{75}{1000} to lowest terms by extracting and canceling out 25.

$$6400\left(1+\frac{3}{40}\right)^{3}$$

Add 1 and \frac{3}{40} to get \frac{43}{40}.

$$6400\times \left(\frac{43}{40}\right)^{3}$$

Calculate \frac{43}{40} to the power of 3 and get \frac{79507}{64000}.

$$6400\times \frac{79507}{64000}$$

Multiply 6400 and \frac{79507}{64000} to get \frac{79507}{10}.

$$\frac{79507}{10}$$

Factor

$$\frac{43 ^ {3}}{2 \cdot 5} = 7950\frac{7}{10} = 7950.7$$