Solve 64+48=x^2

$$64+48= { x }^{ 2 }$$

Solve for x

$$x=4\sqrt{7}\approx 10.583005244$$

$$x=-4\sqrt{7}\approx -10.583005244$$

Steps by Finding Square Root

Add 64 and 48 to get 112.

$$112=x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=112$$

Take the square root of both sides of the equation.

$$x=4\sqrt{7} x=-4\sqrt{7}$$

Steps Using the Quadratic Formula

Add 64 and 48 to get 112.

$$112=x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=112$$

Subtract 112 from both sides.

$$x^{2}-112=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -112 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-112\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-112\right)}}{2}$$

Multiply -4 times -112.

$$x=\frac{0±\sqrt{448}}{2}$$

Take the square root of 448.

$$x=\frac{0±8\sqrt{7}}{2}$$

Now solve the equation x=\frac{0±8\sqrt{7}}{2} when ± is plus.

$$x=4\sqrt{7}$$

Now solve the equation x=\frac{0±8\sqrt{7}}{2} when ± is minus.

$$x=-4\sqrt{7}$$

The equation is now solved.

$$x=4\sqrt{7} x=-4\sqrt{7}$$