Factor
\left(4z-7\right)\left(16z^{2}+28z+49\right)
Evaluate
64z^{3}-343
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\left(4z-7\right)\left(16z^{2}+28z+49\right)
Rewrite 64z^{3}-343 as \left(4z\right)^{3}-7^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial 16z^{2}+28z+49 is not factored since it does not have any rational roots.
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