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\left(8x^{2}-3y^{5}\right)\left(8x^{2}+3y^{5}\right)
Rewrite 64x^{4}-9y^{10} as \left(8x^{2}\right)^{2}-\left(3y^{5}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).