Solve for x
x=\frac{3\left(y+4\right)}{64}
Solve for y
y=\frac{64x}{3}-4
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64x=3y+12
The equation is in standard form.
\frac{64x}{64}=\frac{3y+12}{64}
Divide both sides by 64.
x=\frac{3y+12}{64}
Dividing by 64 undoes the multiplication by 64.
x=\frac{3y}{64}+\frac{3}{16}
Divide 12+3y by 64.
3y+12=64x
Swap sides so that all variable terms are on the left hand side.
3y=64x-12
Subtract 12 from both sides.
\frac{3y}{3}=\frac{64x-12}{3}
Divide both sides by 3.
y=\frac{64x-12}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{64x}{3}-4
Divide 64x-12 by 3.
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