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\left(4m+7n\right)\left(16m^{2}-28mn+49n^{2}\right)
Rewrite 64m^{3}+343n^{3} as \left(4m\right)^{3}+\left(7n\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).