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\left(8a^{2}-5b\right)\left(8a^{2}+5b\right)
Rewrite 64a^{4}-25b^{2} as \left(8a^{2}\right)^{2}-\left(5b\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).