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64\left(0-x\right)^{2}=2x^{2}
Multiply 0 and 3 to get 0.
64\left(-x\right)^{2}=2x^{2}
Anything plus zero gives itself.
64\left(-1\right)^{2}x^{2}=2x^{2}
Expand \left(-x\right)^{2}.
64\times 1x^{2}=2x^{2}
Calculate -1 to the power of 2 and get 1.
64x^{2}=2x^{2}
Multiply 64 and 1 to get 64.
64x^{2}-2x^{2}=0
Subtract 2x^{2} from both sides.
62x^{2}=0
Combine 64x^{2} and -2x^{2} to get 62x^{2}.
x^{2}=0
Divide both sides by 62. Zero divided by any non-zero number gives zero.
x=0 x=0
Take the square root of both sides of the equation.
x=0
The equation is now solved. Solutions are the same.
64\left(0-x\right)^{2}=2x^{2}
Multiply 0 and 3 to get 0.
64\left(-x\right)^{2}=2x^{2}
Anything plus zero gives itself.
64\left(-1\right)^{2}x^{2}=2x^{2}
Expand \left(-x\right)^{2}.
64\times 1x^{2}=2x^{2}
Calculate -1 to the power of 2 and get 1.
64x^{2}=2x^{2}
Multiply 64 and 1 to get 64.
64x^{2}-2x^{2}=0
Subtract 2x^{2} from both sides.
62x^{2}=0
Combine 64x^{2} and -2x^{2} to get 62x^{2}.
x^{2}=0
Divide both sides by 62. Zero divided by any non-zero number gives zero.
x=\frac{0±\sqrt{0^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±0}{2}
Take the square root of 0^{2}.
x=0
Divide 0 by 2.