Solve 64*(-1/6)+8x+4=0

$$64 \cdot ( - \frac { 1 } { 6 } ) + 8 x + 4 = 0$$

Solve for x

$$x=\frac{5}{6}\approx 0.833333333$$

Steps for Solving Linear Equation

Express 64\left(-\frac{1}{6}\right) as a single fraction.

$$\frac{64\left(-1\right)}{6}+8x+4=0$$

Multiply 64 and -1 to get -64.

$$\frac{-64}{6}+8x+4=0$$

Reduce the fraction \frac{-64}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{32}{3}+8x+4=0$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{32}{3}+8x+\frac{12}{3}=0$$

Since -\frac{32}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{-32+12}{3}+8x=0$$

Add -32 and 12 to get -20.

$$-\frac{20}{3}+8x=0$$

Add \frac{20}{3} to both sides. Anything plus zero gives itself.

$$8x=\frac{20}{3}$$

Divide both sides by 8.

$$x=\frac{\frac{20}{3}}{8}$$

Express \frac{\frac{20}{3}}{8} as a single fraction.

$$x=\frac{20}{3\times 8}$$

Multiply 3 and 8 to get 24.

$$x=\frac{20}{24}$$

Reduce the fraction \frac{20}{24} to lowest terms by extracting and canceling out 4.

$$x=\frac{5}{6}$$