Solve 64^-1*4^4:(2^-3)

$$64 ^ { - 1 } \cdot 4 ^ { 4 } : ( 2 ^ { - 3 } )$$

Evaluate

$$32$$

Solution Steps

Calculate 64 to the power of -1 and get \frac{1}{64}.

$$\frac{\frac{1}{64}\times 4^{4}}{2^{-3}}$$

Calculate 4 to the power of 4 and get 256.

$$\frac{\frac{1}{64}\times 256}{2^{-3}}$$

Multiply \frac{1}{64} and 256 to get 4.

$$\frac{4}{2^{-3}}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{4}{\frac{1}{8}}$$

Divide 4 by \frac{1}{8} by multiplying 4 by the reciprocal of \frac{1}{8}.

$$4\times 8$$

Multiply 4 and 8 to get 32.

$$32$$

Factor

$$2^{5}$$