Solve 64^frac{2{3}}-25^frac{3{6}}+27^frac{2{3}}

$$64 ^ { \frac { 2 } { 3 } } - 25 ^ { \frac { 3 } { 6 } } + 27 ^ { \frac { 2 } { 3 } }$$

Evaluate

$$20$$

Solution Steps

Calculate 64 to the power of \frac{2}{3} and get 16.

$$16-25^{\frac{3}{6}}+27^{\frac{2}{3}}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$16-25^{\frac{1}{2}}+27^{\frac{2}{3}}$$

Calculate 25 to the power of \frac{1}{2} and get 5.

$$16-5+27^{\frac{2}{3}}$$

Subtract 5 from 16 to get 11.

$$11+27^{\frac{2}{3}}$$

Calculate 27 to the power of \frac{2}{3} and get 9.

$$11+9$$

Add 11 and 9 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$