Factor
\left(3u+4\right)\left(9u^{2}-12u+16\right)
Evaluate
27u^{3}+64
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\left(3u+4\right)\left(9u^{2}-12u+16\right)
Rewrite 64+27u^{3} as \left(3u\right)^{3}+4^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). Polynomial 9u^{2}-12u+16 is not factored since it does not have any rational roots.
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