Solve 64+25-AC^2=40

$$64 + 25 - A C ^ { 2 } = 40$$

Solve for A

$$A=\frac{49}{C^{2}}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Add 64 and 25 to get 89.

$$89-AC^{2}=40$$

Subtract 89 from both sides.

$$-AC^{2}=40-89$$

Subtract 89 from 40 to get -49.

$$-AC^{2}=-49$$

The equation is in standard form.

$$\left(-C^{2}\right)A=-49$$

Divide both sides by -C^{2}.

$$\frac{\left(-C^{2}\right)A}{-C^{2}}=-\frac{49}{-C^{2}}$$

Dividing by -C^{2} undoes the multiplication by -C^{2}.

$$A=-\frac{49}{-C^{2}}$$

Divide -49 by -C^{2}.

$$A=\frac{49}{C^{2}}$$

Solve for C

$$C=\frac{7}{\sqrt{A}}$$

$$C=-\frac{7}{\sqrt{A}}\text{, }A>0$$