Solve 63*4/9+3r-2/5+1/5

$$63 \cdot \frac { 4 } { 9 } + 3 r - \frac { 2 } { 5 } + \frac { 1 } { 5 }$$

Evaluate

$$3r+\frac{139}{5}$$

Solution Steps

Express 63\times \frac{4}{9} as a single fraction.

$$\frac{63\times 4}{9}+3r-\frac{2}{5}+\frac{1}{5}$$

Multiply 63 and 4 to get 252.

$$\frac{252}{9}+3r-\frac{2}{5}+\frac{1}{5}$$

Divide 252 by 9 to get 28.

$$28+3r-\frac{2}{5}+\frac{1}{5}$$

Convert 28 to fraction \frac{140}{5}.

$$\frac{140}{5}+3r-\frac{2}{5}+\frac{1}{5}$$

Since \frac{140}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{140-2}{5}+3r+\frac{1}{5}$$

Subtract 2 from 140 to get 138.

$$\frac{138}{5}+3r+\frac{1}{5}$$

Since \frac{138}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$\frac{138+1}{5}+3r$$

Add 138 and 1 to get 139.

$$\frac{139}{5}+3r$$

Factor

$$\frac{15r+139}{5}$$

Solution Steps

Factor out \frac{1}{5}.

$$\frac{139+15r}{5}$$

Consider 140+15r-2+1. Multiply and combine like terms.

$$15r+139$$

Rewrite the complete factored expression.

$$\frac{15r+139}{5}$$