Solve 6280=1/3*3.14*(20)^2*h

$$6280 = \frac { 1 } { 3 } \times 3.14 \times ( 20 ) ^ { 2 } \times h$$

Solve for h

$$h=15$$

Steps for Solving Linear Equation

Convert decimal number 3.14 to fraction \frac{314}{100}. Reduce the fraction \frac{314}{100} to lowest terms by extracting and canceling out 2.

$$6280=\frac{1}{3}\times \frac{157}{50}\times 20^{2}h$$

Multiply \frac{1}{3} times \frac{157}{50} by multiplying numerator times numerator and denominator times denominator.

$$6280=\frac{1\times 157}{3\times 50}\times 20^{2}h$$

Do the multiplications in the fraction \frac{1\times 157}{3\times 50}.

$$6280=\frac{157}{150}\times 20^{2}h$$

Calculate 20 to the power of 2 and get 400.

$$6280=\frac{157}{150}\times 400h$$

Express \frac{157}{150}\times 400 as a single fraction.

$$6280=\frac{157\times 400}{150}h$$

Multiply 157 and 400 to get 62800.

$$6280=\frac{62800}{150}h$$

Reduce the fraction \frac{62800}{150} to lowest terms by extracting and canceling out 50.

$$6280=\frac{1256}{3}h$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1256}{3}h=6280$$

Multiply both sides by \frac{3}{1256}, the reciprocal of \frac{1256}{3}.

$$h=6280\times \frac{3}{1256}$$

Express 6280\times \frac{3}{1256} as a single fraction.

$$h=\frac{6280\times 3}{1256}$$

Multiply 6280 and 3 to get 18840.

$$h=\frac{18840}{1256}$$

Divide 18840 by 1256 to get 15.

$$h=15$$