Solve 625=c^2

$$625 = c ^ { 2 }$$

Solve for c

$$c=25$$

$$c=-25$$

Steps Using Difference of Squares

Swap sides so that all variable terms are on the left hand side.

$$c^{2}=625$$

Subtract 625 from both sides.

$$c^{2}-625=0$$

Consider c^{2}-625. Rewrite c^{2}-625 as c^{2}-25^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(c-25\right)\left(c+25\right)=0$$

To find equation solutions, solve c-25=0 and c+25=0.

$$c=25 c=-25$$

Steps by Finding Square Root

Swap sides so that all variable terms are on the left hand side.

$$c^{2}=625$$

Take the square root of both sides of the equation.

$$c=25 c=-25$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$c^{2}=625$$

Subtract 625 from both sides.

$$c^{2}-625=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -625 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$c=\frac{0±\sqrt{0^{2}-4\left(-625\right)}}{2}$$

Square 0.

$$c=\frac{0±\sqrt{-4\left(-625\right)}}{2}$$

Multiply -4 times -625.

$$c=\frac{0±\sqrt{2500}}{2}$$

Take the square root of 2500.

$$c=\frac{0±50}{2}$$

Now solve the equation c=\frac{0±50}{2} when ± is plus. Divide 50 by 2.

$$c=25$$

Now solve the equation c=\frac{0±50}{2} when ± is minus. Divide -50 by 2.

$$c=-25$$

The equation is now solved.

$$c=25 c=-25$$