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x\left(60-2x\right)=0
Factor out x.
x=0 x=30
To find equation solutions, solve x=0 and 60-2x=0.
-2x^{2}+60x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-60±\sqrt{60^{2}}}{2\left(-2\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 60 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-60±60}{2\left(-2\right)}
Take the square root of 60^{2}.
x=\frac{-60±60}{-4}
Multiply 2 times -2.
x=\frac{0}{-4}
Now solve the equation x=\frac{-60±60}{-4} when ± is plus. Add -60 to 60.
x=0
Divide 0 by -4.
x=-\frac{120}{-4}
Now solve the equation x=\frac{-60±60}{-4} when ± is minus. Subtract 60 from -60.
x=30
Divide -120 by -4.
x=0 x=30
The equation is now solved.
-2x^{2}+60x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-2x^{2}+60x}{-2}=\frac{0}{-2}
Divide both sides by -2.
x^{2}+\frac{60}{-2}x=\frac{0}{-2}
Dividing by -2 undoes the multiplication by -2.
x^{2}-30x=\frac{0}{-2}
Divide 60 by -2.
x^{2}-30x=0
Divide 0 by -2.
x^{2}-30x+\left(-15\right)^{2}=\left(-15\right)^{2}
Divide -30, the coefficient of the x term, by 2 to get -15. Then add the square of -15 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-30x+225=225
Square -15.
\left(x-15\right)^{2}=225
Factor x^{2}-30x+225. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-15\right)^{2}}=\sqrt{225}
Take the square root of both sides of the equation.
x-15=15 x-15=-15
Simplify.
x=30 x=0
Add 15 to both sides of the equation.