Solve 606=15000(1+y/2)^2x

$$606 = 15000 ( 1 + \frac { y } { 2 } ) ^ { 2 x }$$

Solve for x (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(\frac{y+2}{2})}-\frac{\log_{\frac{y+2}{2}}\left(\frac{2500}{101}\right)}{2}$$

$$n_{1}\in \mathrm{Z}$$

$$y\neq 0\text{ and }y\neq -2$$

Solve for y (complex solution)

$$y=2\left(e^{\frac{\pi n_{1}\left(-Im(x)-iRe(x)\right)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}}\times 50^{\frac{-Re(x)+iIm(x)}{\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}}}\times 101^{\frac{Re(x)-iIm(x)}{2\left(\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}\right)}}-1\right)$$

$$n_{1}\in \mathrm{Z}$$

$$\left(Re(x)\right)^{2}+\left(Im(x)\right)^{2}\neq 0$$

Solve for x

$$\left\{\begin{matrix}x=\frac{\log_{\frac{y+2}{2}}\left(\frac{101}{2500}\right)}{2}\text{, }&y\neq 0\text{ and }y>-2\\x=\frac{\log_{-\frac{y+2}{2}}\left(\frac{101}{2500}\right)}{2}\text{, }&y\neq -4\text{ and }Numerator(\frac{\ln(\frac{101}{2500})}{2\ln(-\left(\frac{y}{2}+1\right))})\text{bmod}2=1\text{ and }Denominator(\frac{\ln(\frac{101}{2500})}{2\ln(-\left(\frac{y}{2}+1\right))})\text{bmod}2=1\text{ and }y<-2\text{ and }Denominator(\frac{\ln(\frac{101}{2500})}{\ln(-\left(\frac{y}{2}+1\right))})\text{bmod}2=1\text{ and }\left(|\frac{y}{2}+1|\right)^{\frac{\ln(\frac{101}{2500})}{2\ln(-\left(\frac{y}{2}+1\right))}}=\frac{\sqrt{101}}{50}\end{matrix}\right.$$

Solve for y

$$\left\{\begin{matrix}y=2\times \left(\frac{\sqrt{101}}{50}\right)^{\frac{1}{x}}-2\text{, }&x\neq 0\\y=-2\times \left(\frac{\sqrt{101}}{50}\right)^{\frac{1}{x}}-2\text{, }&x\neq 0\text{ and }Numerator(x)\text{bmod}2=0\text{ and }Denominator(x)\text{bmod}2=1\\y=-2\left(-\frac{\sqrt{101}}{50}\right)^{\frac{1}{x}}-2\text{, }&Numerator(x)\text{bmod}2=1\text{ and }Numerator(x)\text{bmod}2=0\text{ and }Denominator(x)\text{bmod}2=1\text{ and }\left(-\frac{\sqrt{101}}{50}\right)^{\frac{1}{x}}\neq 0\\y=2\left(-\frac{\sqrt{101}}{50}\right)^{\frac{1}{x}}-2\text{, }&Numerator(x)\text{bmod}2=1\text{ and }Denominator(x)\text{bmod}2=1\text{ and }\left(-\frac{\sqrt{101}}{50}\right)^{\frac{1}{x}}\neq 0\end{matrix}\right.$$