Solve 600+03*2000+(x-2000)

$$600 + 03 \times 2000 + ( x - 2000 )$$

Evaluate

$$x-1400$$

Solution Steps

Multiply 0 and 3 to get 0.

$$600+0\times 2000+x-2000$$

Multiply 0 and 2000 to get 0.

$$600+0+x-2000$$

Add 600 and 0 to get 600.

$$600+x-2000$$

Subtract 2000 from 600 to get -1400.

$$-1400+x$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Multiply 0 and 3 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(600+0\times 2000+x-2000)$$

Multiply 0 and 2000 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(600+0+x-2000)$$

Add 600 and 0 to get 600.

$$\frac{\mathrm{d}}{\mathrm{d}x}(600+x-2000)$$

Subtract 2000 from 600 to get -1400.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-1400+x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$