Solve 60(40-x)+45xleq2140

$$60(40-x)+45x \leq 2140$$

Solve for x

$$x\geq \frac{52}{3}$$

Solution Steps

Use the distributive property to multiply 60 by 40-x.

$$2400-60x+45x\leq 2140$$

Combine -60x and 45x to get -15x.

$$2400-15x\leq 2140$$

Subtract 2400 from both sides.

$$-15x\leq 2140-2400$$

Subtract 2400 from 2140 to get -260.

$$-15x\leq -260$$

Divide both sides by -15. Since -15 is negative, the inequality direction is changed.

$$x\geq \frac{-260}{-15}$$

Reduce the fraction \frac{-260}{-15} to lowest terms by extracting and canceling out -5.

$$x\geq \frac{52}{3}$$