Solve 60(1-t)^2=486

$$60 ( 1 - t ) ^ { 2 } = 486$$

Solve for t

$$t=-\frac{9\sqrt{10}}{10}+1\approx -1.846049894$$

$$t=\frac{9\sqrt{10}}{10}+1\approx 3.846049894$$

Steps by Finding Square Root

Divide both sides by 60.

$$\frac{60\left(-t+1\right)^{2}}{60}=\frac{486}{60}$$

Dividing by 60 undoes the multiplication by 60.

$$\left(-t+1\right)^{2}=\frac{486}{60}$$

Reduce the fraction \frac{486}{60} to lowest terms by extracting and canceling out 6.

$$\left(-t+1\right)^{2}=\frac{81}{10}$$

Take the square root of both sides of the equation.

$$-t+1=\frac{9\sqrt{10}}{10} -t+1=-\frac{9\sqrt{10}}{10}$$

Subtract 1 from both sides of the equation.

$$-t+1-1=\frac{9\sqrt{10}}{10}-1 -t+1-1=-\frac{9\sqrt{10}}{10}-1$$

Subtracting 1 from itself leaves 0.

$$-t=\frac{9\sqrt{10}}{10}-1 -t=-\frac{9\sqrt{10}}{10}-1$$

Subtract 1 from \frac{9\sqrt{10}}{10}.

$$-t=\frac{9\sqrt{10}}{10}-1$$

Subtract 1 from -\frac{9\sqrt{10}}{10}.

$$-t=-\frac{9\sqrt{10}}{10}-1$$

Divide both sides by -1.

$$\frac{-t}{-1}=\frac{\frac{9\sqrt{10}}{10}-1}{-1} \frac{-t}{-1}=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$t=\frac{\frac{9\sqrt{10}}{10}-1}{-1} t=\frac{-\frac{9\sqrt{10}}{10}-1}{-1}$$

Divide \frac{9\sqrt{10}}{10}-1 by -1.

$$t=-\frac{9\sqrt{10}}{10}+1$$

Divide -\frac{9\sqrt{10}}{10}-1 by -1.

$$t=\frac{9\sqrt{10}}{10}+1$$

The equation is now solved.

$$t=-\frac{9\sqrt{10}}{10}+1 t=\frac{9\sqrt{10}}{10}+1$$