Solve 60(1-t)^2=48.6

$$60 ( 1 - t ) ^ { 2 } = 48.6$$

Solve for t

$$t=0.1$$

$$t=1.9$$

Steps by Finding Square Root

Divide both sides by 60.

$$\frac{60\left(-t+1\right)^{2}}{60}=\frac{48.6}{60}$$

Dividing by 60 undoes the multiplication by 60.

$$\left(-t+1\right)^{2}=\frac{48.6}{60}$$

Divide 48.6 by 60.

$$\left(-t+1\right)^{2}=0.81$$

Take the square root of both sides of the equation.

$$-t+1=\frac{9}{10} -t+1=-\frac{9}{10}$$

Subtract 1 from both sides of the equation.

$$-t+1-1=\frac{9}{10}-1 -t+1-1=-\frac{9}{10}-1$$

Subtracting 1 from itself leaves 0.

$$-t=\frac{9}{10}-1 -t=-\frac{9}{10}-1$$

Subtract 1 from \frac{9}{10}.

$$-t=-\frac{1}{10}$$

Subtract 1 from -\frac{9}{10}.

$$-t=-\frac{19}{10}$$

Divide both sides by -1.

$$\frac{-t}{-1}=-\frac{\frac{1}{10}}{-1} \frac{-t}{-1}=-\frac{\frac{19}{10}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$t=-\frac{\frac{1}{10}}{-1} t=-\frac{\frac{19}{10}}{-1}$$

Divide -\frac{1}{10} by -1.

$$t=\frac{1}{10}$$

Divide -\frac{19}{10} by -1.

$$t=\frac{19}{10}$$

The equation is now solved.

$$t=\frac{1}{10} t=\frac{19}{10}$$