Solve 60*(1+x)^2=198.6

$$60 \times ( 1 + x ) ^ { 2 } = 198.6$$

Solve for x

$$x=\frac{\sqrt{331}}{10}-1\approx 0.81934054$$

$$x=-\frac{\sqrt{331}}{10}-1\approx -2.81934054$$

Steps by Finding Square Root

Divide both sides by 60.

$$\frac{60\left(x+1\right)^{2}}{60}=\frac{198.6}{60}$$

Dividing by 60 undoes the multiplication by 60.

$$\left(x+1\right)^{2}=\frac{198.6}{60}$$

Divide 198.6 by 60.

$$\left(x+1\right)^{2}=3.31$$

Take the square root of both sides of the equation.

$$x+1=\frac{\sqrt{331}}{10} x+1=-\frac{\sqrt{331}}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{\sqrt{331}}{10}-1 x+1-1=-\frac{\sqrt{331}}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{\sqrt{331}}{10}-1 x=-\frac{\sqrt{331}}{10}-1$$