Solve 60+{2*[7+18div(13-8)]}-[7*3-18-2+13]

$$60 + \{ 2 \cdot [ 7 + 18 \div ( 13 - 8 ) ] \} - [ 7 \cdot 3 - 18 - 2 + 13 ]$$

Evaluate

$$\frac{336}{5}=67.2$$

Solution Steps

Subtract 8 from 13 to get 5.

$$60+2\left(7+\frac{18}{5}\right)-\left(7\times 3-18-2+13\right)$$

Convert 7 to fraction \frac{35}{5}.

$$60+2\left(\frac{35}{5}+\frac{18}{5}\right)-\left(7\times 3-18-2+13\right)$$

Since \frac{35}{5} and \frac{18}{5} have the same denominator, add them by adding their numerators.

$$60+2\times \frac{35+18}{5}-\left(7\times 3-18-2+13\right)$$

Add 35 and 18 to get 53.

$$60+2\times \frac{53}{5}-\left(7\times 3-18-2+13\right)$$

Express 2\times \frac{53}{5} as a single fraction.

$$60+\frac{2\times 53}{5}-\left(7\times 3-18-2+13\right)$$

Multiply 2 and 53 to get 106.

$$60+\frac{106}{5}-\left(7\times 3-18-2+13\right)$$

Convert 60 to fraction \frac{300}{5}.

$$\frac{300}{5}+\frac{106}{5}-\left(7\times 3-18-2+13\right)$$

Since \frac{300}{5} and \frac{106}{5} have the same denominator, add them by adding their numerators.

$$\frac{300+106}{5}-\left(7\times 3-18-2+13\right)$$

Add 300 and 106 to get 406.

$$\frac{406}{5}-\left(7\times 3-18-2+13\right)$$

Multiply 7 and 3 to get 21.

$$\frac{406}{5}-\left(21-18-2+13\right)$$

Subtract 18 from 21 to get 3.

$$\frac{406}{5}-\left(3-2+13\right)$$

Subtract 2 from 3 to get 1.

$$\frac{406}{5}-\left(1+13\right)$$

Add 1 and 13 to get 14.

$$\frac{406}{5}-14$$

Convert 14 to fraction \frac{70}{5}.

$$\frac{406}{5}-\frac{70}{5}$$

Since \frac{406}{5} and \frac{70}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{406-70}{5}$$

Subtract 70 from 406 to get 336.

$$\frac{336}{5}$$

Factor

$$\frac{2 ^ {4} \cdot 3 \cdot 7}{5} = 67\frac{1}{5} = 67.2$$