Solve for g
\left\{\begin{matrix}\\g=0\text{, }&\text{unconditionally}\\g\in \mathrm{R}\text{, }&k=-\frac{67}{10}\end{matrix}\right.
Solve for k
\left\{\begin{matrix}\\k=-6.7\text{, }&\text{unconditionally}\\k\in \mathrm{R}\text{, }&g=0\end{matrix}\right.
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6.7g-\left(-k\right)g=0
Subtract \left(-k\right)g from both sides.
6.7g+kg=0
Multiply -1 and -1 to get 1.
\left(6.7+k\right)g=0
Combine all terms containing g.
\left(k+6.7\right)g=0
The equation is in standard form.
g=0
Divide 0 by 6.7+k.
\left(-k\right)g=6.7g
Swap sides so that all variable terms are on the left hand side.
-gk=6.7g
Reorder the terms.
\left(-g\right)k=\frac{67g}{10}
The equation is in standard form.
\frac{\left(-g\right)k}{-g}=\frac{67g}{10\left(-g\right)}
Divide both sides by -g.
k=\frac{67g}{10\left(-g\right)}
Dividing by -g undoes the multiplication by -g.
k=-\frac{67}{10}
Divide \frac{67g}{10} by -g.
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