Solve 6.112*{(e)^frac{17.67*(263.73-273.15){243.5+(263.73-273.15)}}}

$$6.112 \times {(e)^{ \frac{ 17.67 \times (263.73-273.15) }{ 243.5+(263.73-273.15) } }}$$

Evaluate

$$\frac{764}{125e^{\frac{43803}{61600}}}\approx 3.001662763$$

Solution Steps

Subtract 273.15 from 263.73 to get -9.42.

$$6.112e^{\frac{17.67\left(-9.42\right)}{243.5+263.73-273.15}}$$

Multiply 17.67 and -9.42 to get -166.4514.

$$6.112e^{\frac{-166.4514}{243.5+263.73-273.15}}$$

Add 243.5 and 263.73 to get 507.23.

$$6.112e^{\frac{-166.4514}{507.23-273.15}}$$

Subtract 273.15 from 507.23 to get 234.08.

$$6.112e^{\frac{-166.4514}{234.08}}$$

Expand \frac{-166.4514}{234.08} by multiplying both numerator and the denominator by 10000.

$$6.112e^{\frac{-1664514}{2340800}}$$

Reduce the fraction \frac{-1664514}{2340800} to lowest terms by extracting and canceling out 38.

$$6.112e^{-\frac{43803}{61600}}$$