Solve for x
x=-\frac{3y}{2}-1
Solve for y
y=\frac{-2x-2}{3}
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-2x-3y=8-6
Subtract 6 from both sides.
-2x-3y=2
Subtract 6 from 8 to get 2.
-2x=2+3y
Add 3y to both sides.
-2x=3y+2
The equation is in standard form.
\frac{-2x}{-2}=\frac{3y+2}{-2}
Divide both sides by -2.
x=\frac{3y+2}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-\frac{3y}{2}-1
Divide 2+3y by -2.
-2x-3y=8-6
Subtract 6 from both sides.
-2x-3y=2
Subtract 6 from 8 to get 2.
-3y=2+2x
Add 2x to both sides.
-3y=2x+2
The equation is in standard form.
\frac{-3y}{-3}=\frac{2x+2}{-3}
Divide both sides by -3.
y=\frac{2x+2}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{-2x-2}{3}
Divide 2+2x by -3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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