Solve 6(5/6x-1/3y)=-3*6

$$6( \frac{ 5 }{ 6 } x- \frac{ 1 }{ 3 } y) = -3 \cdot 6$$

Solve for x

$$x=\frac{2\left(y-9\right)}{5}$$

Steps for Solving Linear Equation

Cancel out 6 on both sides.

$$\frac{5}{6}x-\frac{1}{3}y=-3$$

Add \frac{1}{3}y to both sides.

$$\frac{5}{6}x=-3+\frac{1}{3}y$$

The equation is in standard form.

$$\frac{5}{6}x=\frac{y}{3}-3$$

Divide both sides of the equation by \frac{5}{6}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{6}x}{\frac{5}{6}}=\frac{\frac{y}{3}-3}{\frac{5}{6}}$$

Dividing by \frac{5}{6} undoes the multiplication by \frac{5}{6}.

$$x=\frac{\frac{y}{3}-3}{\frac{5}{6}}$$

Divide -3+\frac{y}{3} by \frac{5}{6} by multiplying -3+\frac{y}{3} by the reciprocal of \frac{5}{6}.

$$x=\frac{2y-18}{5}$$

Solve for y

$$y=\frac{5x}{2}+9$$

Steps for Solving Linear Equation

Cancel out 6 on both sides.

$$\frac{5}{6}x-\frac{1}{3}y=-3$$

Subtract \frac{5}{6}x from both sides.

$$-\frac{1}{3}y=-3-\frac{5}{6}x$$

The equation is in standard form.

$$-\frac{1}{3}y=-\frac{5x}{6}-3$$

Multiply both sides by -3.

$$\frac{-\frac{1}{3}y}{-\frac{1}{3}}=\frac{-\frac{5x}{6}-3}{-\frac{1}{3}}$$

Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.

$$y=\frac{-\frac{5x}{6}-3}{-\frac{1}{3}}$$

Divide -3-\frac{5x}{6} by -\frac{1}{3} by multiplying -3-\frac{5x}{6} by the reciprocal of -\frac{1}{3}.

$$y=\frac{5x}{2}+9$$