Solve 6(27/13)+3x=10

$$6( \frac{ 27 }{ 13 } )+3x=10$$

Solve for x

$$x=-\frac{32}{39}\approx -0.820512821$$

Steps for Solving Linear Equation

Express 6\times \frac{27}{13} as a single fraction.

$$\frac{6\times 27}{13}+3x=10$$

Multiply 6 and 27 to get 162.

$$\frac{162}{13}+3x=10$$

Subtract \frac{162}{13} from both sides.

$$3x=10-\frac{162}{13}$$

Convert 10 to fraction \frac{130}{13}.

$$3x=\frac{130}{13}-\frac{162}{13}$$

Since \frac{130}{13} and \frac{162}{13} have the same denominator, subtract them by subtracting their numerators.

$$3x=\frac{130-162}{13}$$

Subtract 162 from 130 to get -32.

$$3x=-\frac{32}{13}$$

Divide both sides by 3.

$$x=\frac{-\frac{32}{13}}{3}$$

Express \frac{-\frac{32}{13}}{3} as a single fraction.

$$x=\frac{-32}{13\times 3}$$

Multiply 13 and 3 to get 39.

$$x=\frac{-32}{39}$$

Fraction \frac{-32}{39} can be rewritten as -\frac{32}{39} by extracting the negative sign.

$$x=-\frac{32}{39}$$