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y\left(6-y\right)=0
Factor out y.
y=0 y=6
To find equation solutions, solve y=0 and 6-y=0.
-y^{2}+6y=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
y=\frac{-6±\sqrt{6^{2}}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 6 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{-6±6}{2\left(-1\right)}
Take the square root of 6^{2}.
y=\frac{-6±6}{-2}
Multiply 2 times -1.
y=\frac{0}{-2}
Now solve the equation y=\frac{-6±6}{-2} when ± is plus. Add -6 to 6.
y=0
Divide 0 by -2.
y=-\frac{12}{-2}
Now solve the equation y=\frac{-6±6}{-2} when ± is minus. Subtract 6 from -6.
y=6
Divide -12 by -2.
y=0 y=6
The equation is now solved.
-y^{2}+6y=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-y^{2}+6y}{-1}=\frac{0}{-1}
Divide both sides by -1.
y^{2}+\frac{6}{-1}y=\frac{0}{-1}
Dividing by -1 undoes the multiplication by -1.
y^{2}-6y=\frac{0}{-1}
Divide 6 by -1.
y^{2}-6y=0
Divide 0 by -1.
y^{2}-6y+\left(-3\right)^{2}=\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
y^{2}-6y+9=9
Square -3.
\left(y-3\right)^{2}=9
Factor y^{2}-6y+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(y-3\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
y-3=3 y-3=-3
Simplify.
y=6 y=0
Add 3 to both sides of the equation.