Factor
6\left(y+2\right)\left(y^{2}-2y+4\right)
Evaluate
6\left(y^{3}+8\right)
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6\left(y^{3}+8\right)
Factor out 6.
\left(y+2\right)\left(y^{2}-2y+4\right)
Consider y^{3}+8. Rewrite y^{3}+8 as y^{3}+2^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
6\left(y+2\right)\left(y^{2}-2y+4\right)
Rewrite the complete factored expression. Polynomial y^{2}-2y+4 is not factored since it does not have any rational roots.
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