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6y^{2}=-25
Subtract 25 from both sides. Anything subtracted from zero gives its negation.
y^{2}=-\frac{25}{6}
Divide both sides by 6.
y=\frac{5\sqrt{6}i}{6} y=-\frac{5\sqrt{6}i}{6}
The equation is now solved.
6y^{2}+25=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
y=\frac{0±\sqrt{0^{2}-4\times 6\times 25}}{2\times 6}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 0 for b, and 25 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{0±\sqrt{-4\times 6\times 25}}{2\times 6}
Square 0.
y=\frac{0±\sqrt{-24\times 25}}{2\times 6}
Multiply -4 times 6.
y=\frac{0±\sqrt{-600}}{2\times 6}
Multiply -24 times 25.
y=\frac{0±10\sqrt{6}i}{2\times 6}
Take the square root of -600.
y=\frac{0±10\sqrt{6}i}{12}
Multiply 2 times 6.
y=\frac{5\sqrt{6}i}{6}
Now solve the equation y=\frac{0±10\sqrt{6}i}{12} when ± is plus.
y=-\frac{5\sqrt{6}i}{6}
Now solve the equation y=\frac{0±10\sqrt{6}i}{12} when ± is minus.
y=\frac{5\sqrt{6}i}{6} y=-\frac{5\sqrt{6}i}{6}
The equation is now solved.