Solve for x
x=2y+\frac{2}{3}
Solve for y
y=\frac{x}{2}-\frac{1}{3}
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6y+8+x-4x=6
Subtract 4x from both sides.
6y+8-3x=6
Combine x and -4x to get -3x.
8-3x=6-6y
Subtract 6y from both sides.
-3x=6-6y-8
Subtract 8 from both sides.
-3x=-2-6y
Subtract 8 from 6 to get -2.
-3x=-6y-2
The equation is in standard form.
\frac{-3x}{-3}=\frac{-6y-2}{-3}
Divide both sides by -3.
x=\frac{-6y-2}{-3}
Dividing by -3 undoes the multiplication by -3.
x=2y+\frac{2}{3}
Divide -2-6y by -3.
6y+x=4x+6-8
Subtract 8 from both sides.
6y+x=4x-2
Subtract 8 from 6 to get -2.
6y=4x-2-x
Subtract x from both sides.
6y=3x-2
Combine 4x and -x to get 3x.
\frac{6y}{6}=\frac{3x-2}{6}
Divide both sides by 6.
y=\frac{3x-2}{6}
Dividing by 6 undoes the multiplication by 6.
y=\frac{x}{2}-\frac{1}{3}
Divide 3x-2 by 6.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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