Solve 6y+2(y-5)=-6(y+1)-3

$$6 y + 2 ( y - 5 ) = - 6 ( y + 1 ) - 3$$

Solve for y

$$y=\frac{1}{14}\approx 0.071428571$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by y-5.

$$6y+2y-10=-6\left(y+1\right)-3$$

Combine 6y and 2y to get 8y.

$$8y-10=-6\left(y+1\right)-3$$

Use the distributive property to multiply -6 by y+1.

$$8y-10=-6y-6-3$$

Subtract 3 from -6 to get -9.

$$8y-10=-6y-9$$

Add 6y to both sides.

$$8y-10+6y=-9$$

Combine 8y and 6y to get 14y.

$$14y-10=-9$$

Add 10 to both sides.

$$14y=-9+10$$

Add -9 and 10 to get 1.

$$14y=1$$

Divide both sides by 14.

$$y=\frac{1}{14}$$