Solve for x
x=\frac{3y}{2}+\frac{1}{6}
Solve for y
y=\frac{2x}{3}-\frac{1}{9}
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6x=1+9y
Add 9y to both sides.
6x=9y+1
The equation is in standard form.
\frac{6x}{6}=\frac{9y+1}{6}
Divide both sides by 6.
x=\frac{9y+1}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{3y}{2}+\frac{1}{6}
Divide 1+9y by 6.
-9y=1-6x
Subtract 6x from both sides.
\frac{-9y}{-9}=\frac{1-6x}{-9}
Divide both sides by -9.
y=\frac{1-6x}{-9}
Dividing by -9 undoes the multiplication by -9.
y=\frac{2x}{3}-\frac{1}{9}
Divide 1-6x by -9.
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