Solve 6x-2+[3(x-1)+4x+2]=10x

$$6 x - 2 + [ 3 ( x - 1 ) + 4 x + 2 ] = 10 x$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x-1.

$$6x-2+3x-3+4x+2=10x$$

Combine 6x and 3x to get 9x.

$$9x-2-3+4x+2=10x$$

Subtract 3 from -2 to get -5.

$$9x-5+4x+2=10x$$

Combine 9x and 4x to get 13x.

$$13x-5+2=10x$$

Add -5 and 2 to get -3.

$$13x-3=10x$$

Subtract 10x from both sides.

$$13x-3-10x=0$$

Combine 13x and -10x to get 3x.

$$3x-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$3x=3$$

Divide both sides by 3.

$$x=\frac{3}{3}$$

Divide 3 by 3 to get 1.

$$x=1$$