Solve 6x(x-1)=0

$$6 x ( x - 1 ) = 0$$

Solve for x

$$x=1$$

$$x=0$$

Steps Using Factoring

Use the distributive property to multiply 6x by x-1.

$$6x^{2}-6x=0$$

Factor out x.

$$x\left(6x-6\right)=0$$

To find equation solutions, solve x=0 and 6x-6=0.

$$x=0 x=1$$

Steps Using the Quadratic Formula

Use the distributive property to multiply 6x by x-1.

$$6x^{2}-6x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, -6 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}}}{2\times 6}$$

Take the square root of \left(-6\right)^{2}.

$$x=\frac{-\left(-6\right)±6}{2\times 6}$$

The opposite of -6 is 6.

$$x=\frac{6±6}{2\times 6}$$

Multiply 2 times 6.

$$x=\frac{6±6}{12}$$

Now solve the equation x=\frac{6±6}{12} when ± is plus. Add 6 to 6.

$$x=\frac{12}{12}$$

Divide 12 by 12.

$$x=1$$

Now solve the equation x=\frac{6±6}{12} when ± is minus. Subtract 6 from 6.

$$x=\frac{0}{12}$$

Divide 0 by 12.

$$x=0$$

The equation is now solved.

$$x=1 x=0$$

Steps for Completing the Square

Use the distributive property to multiply 6x by x-1.

$$6x^{2}-6x=0$$

Divide both sides by 6.

$$\frac{6x^{2}-6x}{6}=\frac{0}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x^{2}+\left(-\frac{6}{6}\right)x=\frac{0}{6}$$

Divide -6 by 6.

$$x^{2}-x=\frac{0}{6}$$

Divide 0 by 6.

$$x^{2}-x=0$$

Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-x+\left(-\frac{1}{2}\right)^{2}=\left(-\frac{1}{2}\right)^{2}$$

Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-x+\frac{1}{4}=\frac{1}{4}$$

Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{2}\right)^{2}=\frac{1}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{1}{4}}$$

Simplify.

$$x-\frac{1}{2}=\frac{1}{2} x-\frac{1}{2}=-\frac{1}{2}$$

Add \frac{1}{2} to both sides of the equation.

$$x=1 x=0$$