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Solve for x (complex solution)
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6t^{2}+5t+1=0
Substitute t for x^{2}.
t=\frac{-5±\sqrt{5^{2}-4\times 6\times 1}}{2\times 6}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 6 for a, 5 for b, and 1 for c in the quadratic formula.
t=\frac{-5±1}{12}
Do the calculations.
t=-\frac{1}{3} t=-\frac{1}{2}
Solve the equation t=\frac{-5±1}{12} when ± is plus and when ± is minus.
x=-\frac{\sqrt{3}i}{3} x=\frac{\sqrt{3}i}{3} x=-\frac{\sqrt{2}i}{2} x=\frac{\sqrt{2}i}{2}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.