Factor
6\left(x-1\right)\left(x^{2}-8\right)
Evaluate
6\left(x-1\right)\left(x^{2}-8\right)
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6\left(x^{3}-x^{2}-8x+8\right)
Factor out 6.
x^{2}\left(x-1\right)-8\left(x-1\right)
Consider x^{3}-x^{2}-8x+8. Do the grouping x^{3}-x^{2}-8x+8=\left(x^{3}-x^{2}\right)+\left(-8x+8\right), and factor out x^{2} in the first and -8 in the second group.
\left(x-1\right)\left(x^{2}-8\right)
Factor out common term x-1 by using distributive property.
6\left(x-1\right)\left(x^{2}-8\right)
Rewrite the complete factored expression. Polynomial x^{2}-8 is not factored since it does not have any rational roots.
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