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6\left(x^{3}+3x^{2}+3x+1\right)
Factor out 6.
\left(x+1\right)^{3}
Consider x^{3}+3x^{2}+3x+1. Use the binomial cube formula, a^{3}+3a^{2}b+3ab^{2}+b^{3}=\left(a+b\right)^{3}, where a=x and b=1.
6\left(x+1\right)^{3}
Rewrite the complete factored expression.