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6x^{2}=46
Add 46 to both sides. Anything plus zero gives itself.
x^{2}=\frac{46}{6}
Divide both sides by 6.
x^{2}=\frac{23}{3}
Reduce the fraction \frac{46}{6} to lowest terms by extracting and canceling out 2.
x=\frac{\sqrt{69}}{3} x=-\frac{\sqrt{69}}{3}
Take the square root of both sides of the equation.
6x^{2}-46=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 6\left(-46\right)}}{2\times 6}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 0 for b, and -46 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 6\left(-46\right)}}{2\times 6}
Square 0.
x=\frac{0±\sqrt{-24\left(-46\right)}}{2\times 6}
Multiply -4 times 6.
x=\frac{0±\sqrt{1104}}{2\times 6}
Multiply -24 times -46.
x=\frac{0±4\sqrt{69}}{2\times 6}
Take the square root of 1104.
x=\frac{0±4\sqrt{69}}{12}
Multiply 2 times 6.
x=\frac{\sqrt{69}}{3}
Now solve the equation x=\frac{0±4\sqrt{69}}{12} when ± is plus.
x=-\frac{\sqrt{69}}{3}
Now solve the equation x=\frac{0±4\sqrt{69}}{12} when ± is minus.
x=\frac{\sqrt{69}}{3} x=-\frac{\sqrt{69}}{3}
The equation is now solved.