Solve for y
y=\frac{z-6x^{2}}{7}
Solve for x
x=\frac{\sqrt{6\left(z-7y\right)}}{6}
x=-\frac{\sqrt{6\left(z-7y\right)}}{6}\text{, }y\leq \frac{z}{7}
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7y=z-6x^{2}
Subtract 6x^{2} from both sides.
\frac{7y}{7}=\frac{z-6x^{2}}{7}
Divide both sides by 7.
y=\frac{z-6x^{2}}{7}
Dividing by 7 undoes the multiplication by 7.
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