Solve 6x^2+40=3k

$$6 x ^ { 2 } + 40 = 3 k$$

Solve for k

$$k=2x^{2}+\frac{40}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$3k=6x^{2}+40$$

Divide both sides by 3.

$$\frac{3k}{3}=\frac{6x^{2}+40}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$k=\frac{6x^{2}+40}{3}$$

Divide 6x^{2}+40 by 3.

$$k=2x^{2}+\frac{40}{3}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{18k-240}}{6}$$

$$x=\frac{\sqrt{18k-240}}{6}$$

Solve for x

$$x=\frac{\sqrt{18k-240}}{6}$$

$$x=-\frac{\sqrt{18k-240}}{6}\text{, }k\geq \frac{40}{3}$$