Solve for x
x=\frac{4y+1}{3}
Solve for y
y=\frac{3x-1}{4}
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6x=8y+2
The equation is in standard form.
\frac{6x}{6}=\frac{8y+2}{6}
Divide both sides by 6.
x=\frac{8y+2}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{4y+1}{3}
Divide 8y+2 by 6.
8y+2=6x
Swap sides so that all variable terms are on the left hand side.
8y=6x-2
Subtract 2 from both sides.
\frac{8y}{8}=\frac{6x-2}{8}
Divide both sides by 8.
y=\frac{6x-2}{8}
Dividing by 8 undoes the multiplication by 8.
y=\frac{3x-1}{4}
Divide 6x-2 by 8.
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