Solve 6x+my+14=0

$$6 x + m y + 14 = 0$$

Solve for m (complex solution)

$$\left\{\begin{matrix}m=-\frac{2\left(3x+7\right)}{y}\text{, }&y\neq 0\\m\in \mathrm{C}\text{, }&x=-\frac{7}{3}\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 6x from both sides. Anything subtracted from zero gives its negation.

$$my+14=-6x$$

Subtract 14 from both sides.

$$my=-6x-14$$

The equation is in standard form.

$$ym=-6x-14$$

Divide both sides by y.

$$\frac{ym}{y}=\frac{-6x-14}{y}$$

Dividing by y undoes the multiplication by y.

$$m=\frac{-6x-14}{y}$$

Divide -6x-14 by y.

$$m=-\frac{2\left(3x+7\right)}{y}$$

Solve for m

$$\left\{\begin{matrix}m=-\frac{2\left(3x+7\right)}{y}\text{, }&y\neq 0\\m\in \mathrm{R}\text{, }&x=-\frac{7}{3}\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 6x from both sides. Anything subtracted from zero gives its negation.

$$my+14=-6x$$

Subtract 14 from both sides.

$$my=-6x-14$$

The equation is in standard form.

$$ym=-6x-14$$

Divide both sides by y.

$$\frac{ym}{y}=\frac{-6x-14}{y}$$

Dividing by y undoes the multiplication by y.

$$m=\frac{-6x-14}{y}$$

Divide -6x-14 by y.

$$m=-\frac{2\left(3x+7\right)}{y}$$

Solve for x

$$x=-\frac{my}{6}-\frac{7}{3}$$

Steps for Solving Linear Equation

Subtract my from both sides. Anything subtracted from zero gives its negation.

$$6x+14=-my$$

Subtract 14 from both sides.

$$6x=-my-14$$

Divide both sides by 6.

$$\frac{6x}{6}=\frac{-my-14}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=\frac{-my-14}{6}$$

Divide -my-14 by 6.

$$x=-\frac{my}{6}-\frac{7}{3}$$