Solve for x
x=-\frac{4y}{3}+\frac{1}{60}
Solve for y
y=-\frac{3x}{4}+\frac{1}{80}
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6x=\frac{1}{10}-8y
Subtract 8y from both sides.
\frac{6x}{6}=\frac{\frac{1}{10}-8y}{6}
Divide both sides by 6.
x=\frac{\frac{1}{10}-8y}{6}
Dividing by 6 undoes the multiplication by 6.
x=-\frac{4y}{3}+\frac{1}{60}
Divide \frac{1}{10}-8y by 6.
8y=\frac{1}{10}-6x
Subtract 6x from both sides.
\frac{8y}{8}=\frac{\frac{1}{10}-6x}{8}
Divide both sides by 8.
y=\frac{\frac{1}{10}-6x}{8}
Dividing by 8 undoes the multiplication by 8.
y=-\frac{3x}{4}+\frac{1}{80}
Divide \frac{1}{10}-6x by 8.
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